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Self-organization to the edge of ergodicity breaking
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Complex adaptive systems · arXiv 2026

Self-organization to the edge of ergodicity breaking in a complex adaptive system

Nixie S. Lesmana, Ling Feng, Kan Chen, Choy Heng Lai

National University of Singapore (Physics · NUS Cities · Risk Management Institute · Mathematics) · A*STAR Singapore

Give a population of learning agents a hard, rugged problem, start every agent hot, and let the least fit be replaced again and again. Nobody tunes anything, yet the population settles exactly where its learning dynamics is about to lose ergodicity, and there it solves the problem better than any hand-tuned setting.

The claim

Evolution parks learning agents at the edge of ergodicity breaking, because only there can well-adapted agents keep being replaced.

Optimal reward · the ergodicity edge · scale-free avalanches are three readings of one condition: the cascade a replacement sets off branches marginally, \(\sigma\simeq\rho(M)=1\).

Watch it happen · live EvoSK
256 agents, simulated in your browser

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—

Every agent starts hot, with an exploration temperature \(T\) between 1.4 and 2; each newcomer draws \(T\) uniformly from 0 to 2, and the memory is \(\alpha=0.75\). Left: the population, coloured by temperature, turns from red to mostly blue with a few warm agents. Top right: the collective reward climbs to the best level any single fixed temperature reaches (dashed line, read off Fig. 1 of our paper). Bottom right: temperatures pile up below the edge window and are depleted above it.

Two questions for the rest of the page: why does it stop there, and why is that state good?

0 · Context

Self-organized criticality, but for agents that learn

Self-organized criticality is well established for driven, dissipative systems with simple threshold rules: sandpiles, forest fires, the Bak–Sneppen model of evolution. Such systems tune themselves to a critical point, where events of every size occur, without anyone setting a parameter. Their units, however, are all alike, follow fixed rules and pursue nothing.

Classic self-organized criticality
toy models, for comparison

Homogeneous units, threshold rules, no objective.

Real adaptive systems, biological, social or economic, are made of heterogeneous agents that learn and pursue goals. That raises two questions:

  1. Do such systems self-organize to criticality without tuning?
  2. If so, which critical state do they reach, and why that one?

To answer them we built EvoSK, a minimal model made of three standard ingredients:

Landscape

Sherrington–Kirkpatrick spin glass

A rugged landscape: random couplings \(J_{ij}\) between all pairs of agents, with exponentially many locally stable configurations.

Learning

Reinforcement learning

Each agent maximises its own local reward, exploring at its own temperature \(T_i\).

Selection

Bak–Sneppen replacement

At every step the least fit agent is removed and replaced by a newcomer with a random temperature.

Key result

The population reaches the edge of ergodicity breaking of its own learning dynamics. There it shows scale-free avalanches with exponent \(\tau\approx-3/2\) and a collective reward above that of every fixed-temperature setting. All three are one condition, a replacement cascade that branches marginally, and an exact bookkeeping rule of evolution forces the population onto it.

The argument in one picture

The top row is what we observe. The middle row is the one condition that explains all three observations. The bottom row is why evolution goes there. The rest of the page walks through it from top to bottom.

OBSERVED ONE CONDITION WHY EVOLUTION GOES THERE Optimal reward beats every tuned baseline Ergodicity edge runs barely forget Avalanches P(S) ~ S^(−3/2) σ ≃ ρ(M) = 1 replacement cascade branches marginally multi-scale stability repair fixed points lose stability critical branching ⇒ τ = −3/2 Every arrival must die exact birth–death balance …including cold agents each at a rate ~ 1/N Two gates must open strand: needs σ ≳ 1 select: fails for σ > 1 only near σ = 1

Selection has no choice: the only state it can sustain is the marginal one.

1 · Model

Learning on a rugged landscape, plus selection

The SK game

\(N\) agents are all connected to each other, with symmetric random couplings \(J_{ij}=J_{ji}\) drawn from a Gaussian of variance \(1/N\). Each agent \(i\) plays an action \(\sigma_i=\pm1\). It keeps one number, its incentive \(Q_i\), a moving average of its local field \(h_i\) (the summed pull of all other agents), with memory parameter \(\alpha\):

\[ Q_i \leftarrow (1-\alpha)\,Q_i+\alpha\,h_i,\qquad h_i=\sum_j J_{ij}\sigma_j . \]
(1)

It then plays a softmax policy at its exploration temperature \(T\): a cold agent nearly always follows its incentive, a hot agent often does not. Its expected action is \(m_i\):

\[ \mathbb{P}(\sigma_i=\pm1)\propto e^{\pm Q_i/T},\qquad m_i=\tanh(Q_i/T) . \]
(2)

(Each agent really keeps a value for both actions; since both start at zero and receive opposite rewards, one number \(Q_i\) carries all the information.) Each agent's reward is its own local stability \(\lambda_i\): positive when it plays with its field, negative when it plays against it. Summed over agents, the collective reward is minus twice the SK energy \(E=-\tfrac12\sum_{ij}J_{ij}\sigma_i\sigma_j\):

\[ R_i=\sigma_i h_i\equiv\lambda_i,\qquad \langle R\rangle=-2E/N . \]
(3)

So collective optimality is the classic hard problem of finding low-energy states of a spin glass. Because the couplings are symmetric, this is a potential game: when one agent switches action, its reward changes by exactly \(-\Delta E\). Learning therefore settles into satisficing states, mutual best responses in which every action is aligned with its field and no agent can gain by switching alone. There are exponentially many of them, almost all far above the ground state: individually optimal, collectively suboptimal.

The SK game · 64 agents
try the temperature slider
T 0.30
⟨R⟩ = —flip rate —steps 0

Agents are coloured by their stability \(\lambda_i\): stable, marginal, misaligned. Chords show the strongest couplings. Low \(T\) freezes the population into one satisficing state; high \(T\) randomises it.

EvoSK: add Bak–Sneppen selection

Now temperature becomes a per-agent trait, and the population evolves. Every replacement step has three parts:

  1. Play. Every agent updates \(Q_i\) and acts at its own \(T_i\) (two updates per step).
  2. Evaluate. Fitness is \(f_i=\sigma_i Q_i\), the value of the action the agent took.
  3. Replace the least fit agent with a blank-slate newcomer: \(Q\to0\) and a fresh temperature drawn uniformly from \([0,2]\).
One EvoSK step, slowed down
12-agent toy of the real update loop

The kernel for new temperatures is flat, so any structure in the surviving temperatures is made by selection alone. The only knob left is the memory \(\alpha\); temperature is now the population's choice.

Every agent's reward is its own stability; the collective reward is the energy; temperature is left to evolution.

2 · Three signatures

Optimal, at the edge of ergodicity, and scale-free

1 · Evolution beats every tuned temperature

The long-run collective reward of EvoSK has a broad near-optimal plateau for memory \(\alpha\approx0.3\)–\(0.8\): long memory gets stuck, short memory over-explores. At \(\alpha=0.75\), EvoSK (purple band) lies above the SK game at every fixed temperature (black curve).

Control

Freeze the evolved temperatures and rerun the plain SK game: it falls below the fixed-\(T\) optimum (green band). The gain is in the evolutionary dynamics, not in the traits it ends up with.

Top: collective reward of EvoSK against memory alpha, a plateau near 1.45 between 0.3 and 0.8. Bottom: reward of the SK game against fixed temperature at alpha 0.75, peaking near 1.44 at T = 0.2; the EvoSK band lies above it and the frozen-trait band below.
Optimality. Top: EvoSK reward against memory \(\alpha\). Bottom: SK game at fixed \(T\) (black), EvoSK (purple band), SK with the evolved temperatures frozen (green band). Fig. 1 of our paper. Tap to enlarge.

2 · The evolved population sits at the edge of ergodicity

Is the learning dynamics ergodic, meaning that independent runs forget where they started and agree on their long-run behaviour? We measure this with an ergodicity coefficient \(\epsilon\): the median total-variation distance between the steady-state reward distributions \(\mu,\nu\) of independent runs with the same temperatures,

\[ \epsilon=\operatorname{median}_{\mu,\nu}\lVert\mu-\nu\rVert_{\rm TV} . \]
(4)

\(\epsilon\approx0\) means ergodic (runs mix), \(\epsilon\approx1\) means ergodicity is broken (each run keeps its basin), and values in between mark the edge. To locate the evolved state, we rescale all evolved temperatures together, \(T_i\to T_i\,2^\lambda\), and sweep the perturbation strength \(\lambda\); \(\lambda=0\) is the evolved population itself.

Six panels, one per memory alpha, of the ergodicity coefficient against perturbation strength lambda: it falls from 1 to 0, and at lambda = 0 (the evolved state) it sits on the falling part for alpha 0.5 to 0.8.
The ergodicity edge. \(\epsilon\) against the rescaling \(\lambda\) for six memory values; the green dashed line at \(\lambda=0\) is the evolved state, the grey dashed line the initial temperatures. Fig. 2 of our paper. Tap to enlarge.

For \(\alpha=0.5\)–\(0.8\) the evolved state sits where \(\epsilon\) changes fastest. At \(\alpha=0.3\) it lies on the breaking side, at \(0.9\) on the ergodic side.

The initial temperatures give \(\epsilon\approx0\) for every \(\alpha\): the starting population is ergodic. The edge is reached, not inherited.

3 · Scale-free avalanches, \(\tau\approx-3/2\)

As in the Bak–Sneppen model, we define an avalanche by the population's minimum fitness: it starts when the minimum drops by more than a threshold \(\delta\), and lasts until it has recovered. Its size \(S\) counts the agent updates spent below that level.

The size distribution \(P(S)\) is a power law over nearly four decades with exponent \(\tau=-1.58\) (quartiles \(-1.68\), \(-1.44\)), measured in the window of \(\delta\) where the estimate is stable, and similar for \(\alpha=0.5\)–\(0.8\).

A power law alone is not evidence of criticality. Our identification rests instead on how the system responds to a perturbation, measured and computed independently. That is the next section.

Log-log avalanche size distribution at alpha 0.75: straight lines over four decades with median slope -1.58; inset: slope against the threshold delta, flat near -1.5.
Avalanches. \(\alpha=0.75\), 25 runs of \(1.5\times10^5\) steps; red: the stable \(\delta\) window. Inset: fitted slope against \(\delta\). Fig. 3 of our paper. Tap to enlarge.

Three signatures. Coincidences, or one thing seen three ways?

3 · One condition

A replacement is a perturbation that branches

Sections 3 to 5 present our extended analysis of the mechanism, which goes beyond the first arXiv version of the paper.

Every replacement perturbs the population. The newcomer probably plays a different action from the agent it replaced, which shifts every local field by an amount of order \(1/\sqrt N\). Agents close to their threshold may flip in response, and every flip shifts the fields again. A replacement therefore triggers a branching process: its ratio \(\sigma\) is the mean number of further flips caused by one flip.

How far does one flip spread?
three populations at fixed T, one action flipped

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0 probes

Coloured cells are where the perturbed copy differs from the original; faint cells have differed at some point. Cold (\(T=0.1\)): the damage heals. Hot (\(T=1.5\)): it becomes extensive. Near \(T=0.3\): most probes die, rare ones run far.

σ < 1

Heals

Each flip triggers fewer than one more.

σ = 1

Scale-free

Most probes die; rare ones run far.

σ > 1

Extensive

Surviving cascades reach a finite fraction of all \(N\) agents.

Shared randomness makes the expected damage linear

Softmax agents flip spontaneously all the time, so how can the damage be measured cleanly? We run two copies with identical couplings and identical random numbers, differing by one flipped action. Agent \(i\) then acts differently exactly when its shared uniform draw \(u_i\) falls between the two copies' policies, which happens with probability

\[ \mathbb{P}[i\text{ differs}]=|p^A_i-p^B_i|=\tfrac12\chi_i\,|\delta Q_i|,\qquad \chi_i=\frac{1-m_i^2}{T_i} . \]
(5)

The susceptibility \(\chi_i\) acts as a valve: it is open only for agents near their threshold. On average, damage then follows the mean update, in which each action is replaced by its expected value \(m_j\): a change \(\delta Q_j\) passes the valve \(\chi_j\), shifts the fields through \(J_{ij}\), and enters the incentives with weight \(\alpha\). The incentive differences evolve linearly,

\[ \delta Q(t{+}1)=M\,\delta Q(t),\qquad M=(1-\alpha)\,\mathbb{I}+\alpha\,J\operatorname{diag}(\chi) , \]
(6)

where \(M\) is the Jacobian of the mean learning update.

Two copies, one shared draw
pick a temperature
T:—

The branching ratio is a spectral radius

The branching ratio is therefore set by the largest eigenvalue magnitude, the spectral radius, of the Jacobian:

\[ \sigma\simeq\rho(M) . \]
(7)

When the population is hot, many valves are open and \(\rho(M)>1\): perturbations grow. When it is cold, the valves are shut and \(\rho(M)<1\): perturbations heal. Counting real flips instead of incentive damage gives a similar matrix, \(\operatorname{diag}(\chi)\,M\operatorname{diag}(\chi)^{-1}\), with the same spectrum. So a statement about cascades is also a statement about the stability of learning.

ρ(M), computed live while cooling
8 SK games, N = 256, Lanczos

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hold T ——

Eight 256-agent SK games at a uniform temperature are cooled step by step from \(T=1\) to \(0.05\). At each temperature the browser equilibrates them and computes the largest eigenvalue of \(M\) exactly, on several snapshots each. The grid shows each agent's valve \(\chi_i\), bright where open. Instantaneous values fluctuate strongly, so the averaging matters.

Approximation: \(M\) is treated as fixed over the steps of one cascade. Since \(\chi\) moves with \(Q\), \(\rho(M)\) only approximates the growth rate of the product \(M(t)M(t{-}1)\cdots\).

Marginal branching is the ergodicity edge

0.304
T where σ = 1, from damage spreading
0.28
T where ρ(M) = 1, no free parameters
[0.15, 0.35]
ε edge window at α = 0.75
0.036
largest σ vs ρ(M) gap across the edge region
Branching ratio sigma (purple) and spectral radius rho(M) (green) against temperature on a log axis; both cross 1 near T = 0.3 inside the grey edge window.
Edge = marginal branching. Uniform-\(T\) game, \(\alpha=0.75\), \(N=256\), 48 disorder samples. Purple: \(\sigma\) from damage spreading; green: \(\rho(M)\); grey: the \(\epsilon\) edge window. Tap to enlarge.

Both crossings sit inside the window where \(\epsilon\) falls from 0.85 to 0.15. The reason is direct: at a satisficing fixed point, \(M\) is the Jacobian.

\(\rho(M)<1\): every fixed point is an attractor → runs keep their basin → \(\epsilon>0\).

\(\rho(M)>1\): no fixed point is stable → runs mix → \(\epsilon\to0\).

A critical branching process has total progeny \(P(S)\sim S^{-3/2}\): the avalanche exponent is derived, not fitted.

At every memory level, three thresholds share one window

Is this special to \(\alpha=0.75\)? For each memory level, the grey bar is the independently measured \(\epsilon\) edge window. The purple dot is the balance boundary \(T_\times\), which comes from the evolution alone (next section); the gold star is \(\sigma=1\) from damage spreading; the green square is \(\rho(M)=1\) from the Jacobian. All three fall inside the window at every \(\alpha\), even though the windows differ a lot.

ε(T) edge window T×: balance boundary ★σ = 1: damage spreading ρ(M) = 1: Jacobian

The ergodicity edge and scale-free avalanches are one condition: \(\sigma\simeq\rho(M)=1\).

4 · Why evolution goes there

Every arrival must die, cold agents included

Exact bookkeeping

Start from bookkeeping that holds exactly. One agent dies per step, and the newcomer's temperature comes from the flat kernel \(u(T)\). Writing \(\rho_t(T)\) for the temperature distribution of the population and \(\kappa_t(T)\) for the distribution of the temperatures of the agents that die,

\[ N\rho_{t+1}(T)=N\rho_t(T)-\kappa_t(T)+u(T) . \]
(8)

In any stationary state the death flux must equal the injection, flat, however uneven the population is. Writing the death flux as \(N\rho\,h\) with a per-capita hazard \(h(T)\):

\[ \kappa^*(T)=u(T)\;\Rightarrow\;\rho^*(T)=\frac{u(T)}{N\,h(T)} . \]
(9)

Temperatures pile up where the hazard is low. The natural boundary is where an agent's expected lifetime equals one turnover of the population, \(h(T_\times)=1/N\). Below \(T_\times\) agents outlive a turnover and are enriched; above it they are replaced within one and are depleted.

Selection–mutation balance
live, N = 128

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—

The standing density skews cold, the death flux stays flat, and the hazard rises by orders of magnitude, crossing \(Nh=1\) near \(T\approx0.3\)–\(0.4\). In our production runs (\(N=256\), \(3.25\times10^6\) events) the death flux is flat to 1.4% while \(\rho^*\) varies 440-fold, and \(T_\times\) lies inside the edge window at every \(\alpha\).

Four panels: (a) flat death flux against T; (b) standing density falling from 10 to 0.01 with a knee near T = 0.33; (c) hazard rising through N h = 1 near T = 0.33; (d) the balance boundary T_x inside the edge window for four memory values.
The balance, measured. (a) Death flux, flat to 1.4%. (b) Standing density \(\hat\rho^*=u/(N\hat h)\). (c) Hazard: floor \(Nh\approx0.08\), plateau \(Nh\approx35\), with an independent-agent prediction that has no fitted parameters; 73% of deaths hit newborns (age ≤ 10). (d) \(T_\times\) inside the edge window at every \(\alpha\); \(T_\times=0.32\)–\(0.35\) for \(N=128\)–\(1024\). Tap to enlarge.

Cold agents must die too, and that takes two gates

Every arrival must die, including newcomers that become cold and well aligned; each of them must be removed at a rate of order \(1/N\). A cold agent can die only in two steps:

Gate 1

Strand

\(S\) persistent flips shift a bystander's field by a Gaussian amount with \(\mathrm{Var}(\Delta h)=4S/N\). Reversing the order-one margin of a cold agent needs \(S\sim N\): a collective rearrangement.

Gate 2

Select

Once stranded, it must be the least fit agent of all before it realigns. Warm agents compete for that slot.

Two gates · toy illustration
three populations held at fixed σ

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cold warm cascade stranded selected

Subcritical (left): cascades are small and nothing strands, so gate 1 is shut. Supercritical (right): large cascades strand plenty, but the warm majority always sits deeper at negative fitness and takes the selection, so gate 2 is shut; warm agents are culled and the population cools. Marginal (middle): power-law cascades strand occasionally and the warm pool is small, so a stranded cold agent is often the minimum. The meter compares the cold share of deaths with what the balance needs.

The window closes onto \(\sigma=1\) as \(N\) grows

The same argument can be done in closed form with a two-class caricature: cold agents with margin \(\lambda_0\), and warm agents that carry the cascades. A cascade of \(S\) persistent flips strands a cold agent with probability about \(e^{-S_*/S}\), with \(S_*=\lambda_0^2N/8\). Averaging over the size law of a critical branching (Galton–Watson) process, all dependence on \(N\) and \(\sigma\) collapses into one variable, \(z=(1-\sigma)\sqrt N\), and the supply condition \(\sqrt N\,e^{-\lambda_0 z/2}\gtrsim1\) gives the lower limit of the window:

\[ 1-\sigma_1\simeq\frac{\ln N}{\lambda_0\sqrt N} . \]
(10)

Above \(\sigma=1\) the other gate shuts: warm agents fill the bottom of the fitness ranking and shield the cold ones from selection. The lower limit is a threshold, not a resting point, and the upper limit is set by shielding, which the argument does not pin down sharply; both converge on 1.

The window shrinks with N
exact sums, λ₀ = 2, illustrative
N 100—
Branching ratio of the evolved state against population size from 128 to 8192: 0.88 at N = 128, rising to about 1.01 from N = 2048.
Measured. Branching ratio of the evolved temperatures against \(N\). Tap to enlarge.

Measured, the evolved population approaches 1 from below: \(\sigma=0.88\) at \(N=128\), saturating at about 1.01 for \(N\ge2048\), within the \(\pm0.015\) bias of our estimator.

At \(N=256\) only about ten warm agents sit above \(T_\times\), and they can fluctuate to nearly none. The population then falls into a degenerate state in which only the newest agent is ever at negative fitness, which satisfies the balance trivially. In \(10^7\)-step runs this happens in 12 of 24 runs at \(N=256\), 2 of 24 at \(N=512\) and none of 8 at \(N=1024\); it explains \(\sigma\approx0.95\) at \(N=256\).

Reached from above in ∼N steps; from below, by aging

Is this state actually reached? We started populations of \(N=1024\) from four different temperature distributions.

Pooled branching ratio against replacement steps for frozen, cold, kernel and hot starts; all approach 1.
From above. Hot and kernel starts relax in \(\tau_+\approx N/p_{\rm est}\approx6N\), where \(p_{\rm est}\approx0.16\) is the fraction of newcomers that become established: measured \(\approx5\times10^3\) steps, predicted \(6\times10^3\). Tap to enlarge.
Fraction of sites still holding their original agent against steps: the kernel start drops to 0.1 by 10^4 steps, the frozen start stays near 0.7 after 4 million steps.
From below. Warm agents refill within \(10^3\) steps (the frozen start jumps from \(\sigma=0.77\) to 0.96), then the original cold agents leave ever more slowly: 68% remain after \(4\times10^6\) steps. Tap to enlarge.
Window-mean reward over 4 million steps: kernel start near 1.487, frozen start rising from 1.449 to 1.459; a single frozen run jumps at a quake near 10^6 steps.
Aging and quakes. Rare collective events replace about 90 original agents at once and lift \(\langle R\rangle\) by about 0.02. Tap to enlarge.
Persistence since step 1000 for the frozen start under three rules: no replacement stays near 0.95, extremal falls to 0.68, random falls to 0 within a few thousand steps.
Controls. Without replacement the frozen start settles in a satisficing state (\(\langle R\rangle\approx1.42\)); random replacement erases the memory and melts (\(0.89\)); extremal replacement ages and improves. Tap to enlarge.

The death flux must stay flat however uneven the population; only near σ = 1 can the cold majority keep being renewed.

5 · Why it is optimal

Extremal selection is stability repair at every scale

Why is the critical state also the best one? Each agent's reward is its local stability, and its fitness is a smoothed copy of it (correlation \(r=0.997\)). Replacing the least fit agent therefore means repairing the least stable site. This is the principle of extremal optimization, known to work best at a border between ergodic and non-ergodic behaviour; here that border is self-organized. Small cascades refine the current basin, rare large ones move the population to a new one.

extremal (EvoSK)1.455
random replacement0.849

Replacing a random agent instead abolishes the self-organization too (\(\langle T\rangle\approx1.0\)).

Same backbone, half the loss

To see where the gain comes from, split the reward by the sign of each agent's stability:

\[ \langle R\rangle=G-L,\qquad G=\int_{\lambda>0}\lambda\,p(\lambda)\,d\lambda,\qquad L=\int_{\lambda<0}|\lambda|\,p(\lambda)\,d\lambda . \]
(11)

The backbone gain \(G\) sums the stability of the aligned agents, those playing with their field: how good a configuration the majority holds. The misalignment loss \(L\) sums \(|\lambda_i|\) over the agents playing against their field: the reward lost to instability.

Temperature sets the width \(w=T/2\) of the flip kernel. A wider kernel explores more of the landscape, so \(G\) rises, but it also knocks more agents out of alignment, so \(L\) rises too. With one temperature for everyone, the two are locked together and trace a frontier, labelled by \(T\).

The evolved population (★) matches the frontier's best \(G\) but pays only 52% of its \(L\) (3.2 standard errors). The cold majority holds the backbone at almost no loss; the warm minority does the exploring and is culled before it accumulates misalignment.

Backbone gain G against misalignment loss L: the constant-T frontier rises to about 1.45 near T = 0.2 and falls; the EvoSK star sits at the frontier's top gain but at about half its loss.
EvoSK lies off the frontier. Grey: one temperature for all, labelled by \(T\). Star: EvoSK. Tap to enlarge.

Optimality is not a separate finding. It is what marginal, extremal repair does.

6 · Generality

Robust to inheritance; three ingredients suffice

We tried four replacement rules: V0 blank slate (the main model); V1 elitist copying of \(q\) and \(T\) without mutation; V2 fitness-biased inheritance with mutation; V3 Darwinian inheritance of \(T\) only. At \(\alpha=0.75\) the rewards are statistically indistinguishable, and at \(\alpha=0.9\) inheritance improves them. All four collapse onto the same ergodicity transition, with \(T_\times\) in the same window. The balance explains why: a replacement rule only changes the offspring distribution, while \(T_\times\) is defined by the hazard for any rule.

Three panels for four replacement rules V0 to V3: (a) similar collective rewards across memory values; (b) the same ergodicity curve against trait rescaling; (c) standing densities of temperature concentrated below the edge window.
Robustness. (a) Reward is preserved. (b) Edge-seeking at \(\alpha=0.75\). (c) Evolved temperatures sit at the edge. Tap to enlarge.

Three general conditions are enough for the mechanism:

(i)

Extremal removal

Removal is rank-based: the least fit goes.

(ii)

Offspring reach the hard class

Some newcomers become established, so the hard class must sustain a death flux.

(iii)

A hard class

Its members can be removed only after collective rearrangements.

The spin glass and the learning rule only decide which critical point; the mechanism is selection.

7 · Summary

One condition, and the reason evolution meets it

Observed

Reward above every fixed \(T\); the evolved state at the \(\epsilon\) edge; avalanches with \(\tau\approx-1.58\).

One condition

\(\sigma\simeq\rho(M)=1\): crossings at \(T=0.304\) and \(0.28\), inside the edge window at every \(\alpha\).

Why there

Every arrival must die; cold agents need to be stranded (\(\sigma\gtrsim1\)) and selected (\(\sigma\lesssim1\)).

What is exact, what is argued, and what is measured:

Exact
  • \(\kappa^*=u\), \(\rho^*=u/(Nh)\), unit death flux
  • \(q^-=-q^+\); \(\langle R\rangle=-2E/N\); \(R_i=\lambda_i\)
  • \(\mathbb{P}[\text{damaged}]=\tfrac12\chi|\delta Q|\) to first order; flip and incentive Jacobians share one spectrum
Argued / approximate
  • \(\sigma\simeq\rho(M)\) assumes a frozen Jacobian over a cascade
  • Why marginal: the two-gate argument and the caricature; they bracket the window, not the side of approach
  • The avalanche statistic as a proxy for branching-process progeny
Measured
  • \(T_\times\), \(\sigma=1\) and \(\rho(M)=1\) inside the edge window at four values of \(\alpha\)
  • \(\sigma(N)\to\approx1.01\) for \(N\ge2048\)
  • Relaxation and aging at \(\alpha=0.75\), 8–24 realisations
Technical note: measuring the branching ratio

We follow the activity \(A(t)\), the number of agents that newly differ at step \(t\), with \(\langle A(t)\rangle\propto\sigma^t\), and fit the ensemble-averaged curve (per-run ratios are biased low where the damage dies). Calibrated on Galton–Watson processes, the bias is at most 0.035 for \(\sigma=0.8\)–\(1.2\) and at most 0.015 near 1. The first step carries a seed transient, \(\langle A(0)\rangle=\alpha\sqrt{2N/\pi}\,\langle\chi\rangle\), from the all-to-one coupling to the seed; including it inflates large-\(N\) estimates to 1.02–1.03, while dropping 4 or 6 initial steps agrees to within 0.005.

Estimator calibration for the branching ratio.
Stalled runs at N = 256: fraction of time in the degenerate state.
Finite size: stalled runs, discussed in section 4.

Criticality and functionality are not two findings here, but one.